Physics, asked by Mister360, 1 month ago

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Answered by CreativeAB
2

★ Question ★

An object of mass 0.4kg moving with a velocity of 4m/s collides with another object of mass 0.6kg moving in same direction with a velocity of 2m/s. If the collision is perfectly inelastic, what is the loss of K.E. due to impact ?

★ Answer ★

Given,

m₁ = 0.4kg, v₁ = 4m/s

m₂ = 0.6kg, v₂ = 2m/s

Since collision is perfectly inelastic, both masses would move together at velocity v.

According to conservation of momentum,

m₁v₁ + m₂v₂ = (m₁ + m₂)v

⇒(0.4) (4) + (0.6) (2) = (0.6 + 0.4)v

⇒1.6 + 1.2 = v

⇒ v = 2.8 m/s

Initial K.E = 0.5m₁ (v₁)² + 0.5m₂ (v₂)²

= (0.5) (0.4) (4)² + (0.5) (0.6) (2)²

= 4.4 J

Final K.E = 0.5 (m₁ + m₂)v²

= (0.5) (1) (2.8)²

= 3.92 J

Loss = Initial K.E - Final K.E = 4.4 - 3.92 = 0.48 J

Regards,

CreativeAB

• The Genius •

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