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Answers
★ Question ★
An object of mass 0.4kg moving with a velocity of 4m/s collides with another object of mass 0.6kg moving in same direction with a velocity of 2m/s. If the collision is perfectly inelastic, what is the loss of K.E. due to impact ?
★ Answer ★
Given,
m₁ = 0.4kg, v₁ = 4m/s
m₂ = 0.6kg, v₂ = 2m/s
Since collision is perfectly inelastic, both masses would move together at velocity v.
According to conservation of momentum,
m₁v₁ + m₂v₂ = (m₁ + m₂)v
⇒(0.4) (4) + (0.6) (2) = (0.6 + 0.4)v
⇒1.6 + 1.2 = v
⇒ v = 2.8 m/s
Initial K.E = 0.5m₁ (v₁)² + 0.5m₂ (v₂)²
= (0.5) (0.4) (4)² + (0.5) (0.6) (2)²
= 4.4 J
Final K.E = 0.5 (m₁ + m₂)v²
= (0.5) (1) (2.8)²
= 3.92 J
Loss = Initial K.E - Final K.E = 4.4 - 3.92 = 0.48 J
Regards,
CreativeAB
• The Genius •