Question

Answer the question in the attachment! ​

Answer 1

Answer:

is 65°

Step-by-step explanation:

25°+35°+55°= 115°

115°-180°= 65°

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Answer 2

$\large\underline{\sf{Solution-}}$

Construction :- Let produce DC to E intersecting AB at E.

Now, in triangle ADE,

We have,

∠ADE = 25°

∠ EAD = 55°

Now, ∠DEB is an exterior angle of a triangle ADE.

We know,

Exterior angle of a triangle is equals to sum of the interior opposite angles.

So, it means

∠DEB = ∠DAE + ∠ADE

∠ DEB = 25° + 55°

$\rm\implies \: \angle \: DEB \: = \: 80 \degree \:$

Now, in triangle CEB

We have,

∠DEB = ∠CEB = 80°

∠CBE = 35°

∠DCB = x°

Now, using exterior angle property of a triangle,

Exterior angle of a triangle is equals to sum of interior opposite angles.

So, it means

∠DCB = ∠CEB + ∠CBE

$\rm \: x = 80 \degree \: + \: 35 \degree$

$\rm\implies \:\rm \: x = 115\degree$

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Additional Information :-

1. The sum of all interior angles of a triangle is supplementary.

2. The sum of exterior angles of a triangle is 360°.

3. Angle opposite to longest side is always greater.

4. Side opposite to greater angle is always longest.

5. Angle opposite to equal sides are always equal.

6. Side opposite to equal angles are equal.