Answer the question in the attachment
Class 11th
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Answered by
1
-1/2 + √3/2 i = w
-1/2 - √3/2. i = w^2
And w^3 = 1
W^20 + w^2)^20 = w^20 + w^40
= w^20( 1 + w^20)
= w^18 w^2 ( 1 + w^18 w^2)
w^18 = 1
So
w^2 ( 1 + w^2)
w^2 + w^4
w^2 + w^3 w
As w^3 = 1
w^2 + w
As 1 + w + w^2 = 0
w+ w^2 = -1
So its -1
D) is correct
SulagnaRoutray:
w^20+w^2)^20
Answered by
0
Answer:
⇒ -1/2 + √3/2 i = w
⇒ -1/2 - √3/2. i = w^2
And w^3 = 1
⇒ W^20+w^2)^20=w^20+w^40
⇒ =w^20(1+w^20)
⇒ =w^18w^2(1+w^18w^2)
⇒ w^18=1
So
⇒ w^2(1+w^2)
⇒ w^2+w^4
⇒ w^2+w^3w
⇒ Asw^3=1
⇒ w^2+w
⇒ As1+w+w^2=0
⇒ w+w^2=-1
= 1
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