Question

answer the question in the attachment

it is from trigromentrical ratio chapter

Ashik which subject exam you will have now​

Answer 1

$➵\text \purple{ Given:- }$

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$➵ \footnotesize\text{ Sin θ = 3/5 }$

$➵ \footnotesize\text{ θ is a acute angle}$

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$➵\text \purple{ Find:- }$

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$➵ \footnotesize\text{ Cos θ = ?}$

$➵ \footnotesize\text{ Tan θ = ?}$

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$➵\text \purple{ Solution:- }$

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$➵ \footnotesize\text{ Sin θ = 3/5}$

$➵ \footnotesize\text{ Sin θ = Perpendicular/Height}$

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$➵ \footnotesize\text \purple{ On comparing the values with the} \\\footnotesize\text \purple{Formula of Sin θ we got to know that }$

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$➵\footnotesize\text{ Perpendicular = 3}$

$➵\footnotesize\text{ Hypotenuse = 5}$

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$➵\footnotesize\text{ Now, Find Base (By Pythagoras Theorem)}$

$➵\footnotesize\text{ (Hypotenuse)² = (Perpendicular)² + (Base)²}$

$➵\footnotesize\text{ (5)² = (3)² + (Base)²}$

$➵\footnotesize\text{ 25 = 9 + (Base)²}$

$➵\footnotesize\text{ 25 - 9 = (Base)²}$

$➵\footnotesize\text{ 16 = (Base)²}$

$➵\footnotesize\text{ √16 = Base}$

$➵ \: \underline{\underline{\boxed{\footnotesize\text \purple{ 4 = Base}}}}$

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$➵\footnotesize\text{ Cos θ = Base/Hypotenuse}$

$➵ \: \underline{\underline{\boxed{\footnotesize\text \purple{ Cos θ = 4/5}}}}$

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$➵\footnotesize\text{ Tan θ = Perpendicular/Base}$

$➵ \: \underline{\underline{\boxed{\footnotesize\text \purple{ Tan θ = 3/4}}}}$