Question

Answer the question in the image

Answer 1

the answer is option (b) 4u^2/g
2gh= v^2-u^2
2gh = (3)^2-(u)^2
2gh = 9u^2 -u^2
2gh = 8u^2
gh = 8u^2/2
h = 4u^2/g
therefore the answer is, (b)
 i hoe that this will help u..........................^_^
 

Answer 2

$\huge\underline\mathfrak\blue{Answer}$

Option [2].

4u²/g is the height of tower.

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$\huge\underline\mathfrak\blue{Explanation}$

Given :

Final velocity (v) = 3u

initial velocity = u

acceleration (a) = g

To find :

Height of the tower.

Solution :

We know that,

v² - u² = 2aS [ By second equation of motion ]

where v is final velocity

u is initial velocity

a is Acceleration

S is distance

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In that case,

The equation will be :

v² - u² = 2gh.....(i)

where, v is final velocity

u is initial velocity

g is Acceleration due to gravity

h is height

From (i) eq,

h = (v²-u²)/2g....(ii)

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Now,

put the given values in (ii) eq.

h = [(3u)² - (u)²]/2g

h = [(9u²) - u²]/2g

h = (9u² - u²)/2g

h = 8u²/2g

h = 4u²/g ( required answer )

Hence, the height of tower is : 4u²/g i.e option [2] is correct!

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