Question

Answer the question.....

jai siya ram __/\__​

Answer 1

Here is your answer........

Answer 2

$\sqrt{\frac{\left(a^{-6}\cdot \:\:b^3\cdot \:\:c^{21}\right)}{c^9\cdot \:\:a^{15}}}$

$\frac{a^{-6}b^3c^{21}}{c^9a^{15}}=\frac{b^3c^{12}}{a^{21}}$

$\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=\frac{1}{x^{b-a}}$

$\frac{a^{-6}}{a^{15}}=\frac{1}{a^{15-\left(-6\right)}}\\\\=\frac{b^3c^{21}}{c^9a^{15-\left(-6\right)}}$

$\mathrm{Subtract\:the\:numbers:}\:15-\left(-6\right)=21$

$=\frac{b^3c^{21}}{a^{21}c^9}$

$\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}$

$\frac{c^{21}}{c^9}=c^{21-9}$

$=\frac{b^3c^{21-9}}{a^{21}}$

$\mathrm{Subtract\:the\:numbers:}\:21-9=12$

$=\frac{b^3c^{12}}{a^{21}}$

$=\sqrt{\frac{b^3c^{12}}{a^{21}}}$