Math, asked by Ravinderkasyap02, 1 year ago

answer the question no 10

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Answered by originaljustice
3
mark it as brainliest
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Answered by anonymous64
1
<b>Heya mate. (^_-). Solution below.
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<u>Your Question -</u>

A sum of money lent at 8% p.a. simple interest for 5 years yields a certain amount of interest. Had it been lent for 7 years, it would have yielded Rs. 960 more. Find the sum.

<u>Solution -</u>

Let the Principal amount/sum (P) be 'x'.

Then, we consider two cases.

\mathcal{Case \: 1}

Principal (P) = x

Rate of interest (R) = 8% p.a.

Time (T) = 5 years

So, simple interest (S.I.)

= (P × R × T)/100

= (x × 8 × 5)/100

= 40x/100.
_______________________

\mathcal{Case\: 2}

P = x

R = 8% p.a.

T = 7 years.

So, S.I.

= (P × R × T)/100

= (x × 8 × 7)/100

= 56x/100.
______________________

Now, according to question,

S.I. for 5 years < S.I. for 7 years by 960.

So, if 960 is added to S.I. for 5 years, it will be equal to S.I. for 7 years.

=> 40x/100 + 960 = 56x/100

=> 960 = 56x/100 - 40x/100

=> 960 = (56x-40x)/100

=> 960 = 16x/100

=> 960 × 100/16 = x

=> 96000/16 = x

=> 6000 = x

=> x = 6000

&lt;marquee&gt;Hence, the sum is Rs. 6000.&lt;/marquee&gt;
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Thank you .. ;-)
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