Question

answer the question of 19

Answer 1

Let the perimeter be x m

Given , width of the path = 2m

Then , area of the path = perimeter × width of the path

=

$2x \: m { }^{2}$

But area given =

$464 \: m {}^{2}$

Then ,

$2x = 464 \\ = > x = 464 \div 2 \\ = > x = 232$

Hence , the perimeter of the park is 232 m

Hope it helps

Answer 2

mark as a brainliest answer

please..