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if xy is the two digit number
sum of it and the number formed by reversing the digits is (10x+y)+(10y+x)=66
and the numbers differ by 2
assuming x>y ,x-y=2
therefore solving the equations
11x+11y=66 => x+y=6
and x-y=2
x=4 y=2 and the number is 42
sum of it and the number formed by reversing the digits is (10x+y)+(10y+x)=66
and the numbers differ by 2
assuming x>y ,x-y=2
therefore solving the equations
11x+11y=66 => x+y=6
and x-y=2
x=4 y=2 and the number is 42
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