Question

answer the question of this physics problem

Answer 1

aloha user!!
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let $v_{a}$ and $v_{b}$ be the velocities of the two bodies A and B.

=> when two bodies move towards each other:

relative velocity of body A w.r.t B:
$v_{ab} = v_{a} - (-v_{b} ) = v_{a} + v_{b}$
since the distance is diminishing by 16m every 10 sec.
v = d/t
v = 16/10 = 1.6 m/s

which means 

$v_{a}+ v_{b} = 1.6$ ----------------(1)

when the two bodies move in the same direction:

relative velocity of body A w.r.t B , v' = $v_{a} -v_{b}$

since the distance increases by 3 m every 5 seconds,

v = d/t
v' = 3/5 = 0.6 m/s

or,


$v_{a} - v_{b} = 0.6$ --------------(2)

by elimination method of eqn (1) and (2) we will get:

 $v_{a} = 1.1 m/s$

$v_{b} = 0.5 m/s$


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