Question

answer the question please

Answer 1

Solution:

Given: To factorize $x^2-5x+15$

$x^2-5x+15$

by using quadratic formula: [tex] \frac{-b± \sqrt{b^2-4ac} }{2a} [/tex]  (neglect A)
where a= 1,b=-5, c= 15

$\frac{-(-5)± \sqrt{(-5)^2-4(1)(15)} }{2(1)}$
$\frac{5± \sqrt{25-60} }2$
$\frac{5± \sqrt{-35} }{2}$  ..
..Discriminant is in negative.
so, $b^2-4ac\ \textless \ 0$
and hence no roots,.

so, no value for x if $x^2-5x+15 =0$
so,we can't factorize.