Question

answer the question please​

Answer 1

Answer:

Step-by-step explanation:

4.Now acc. to triangle,

a=20cm ( height of the window from foot of the building)

b=?

c=25cm (height of the ladder)

By Pythagoras theorem,

AC²+BC²=AB²

⇒b²+ (20)² = (25)²

⇒b² = (25)² - (20)²

⇒b² = 625-400

⇒b² = 225

⇒b = √225

⇒b = 15cm

Hence, distance of the foot of the ladder to the building is 15cm.

5. ABC is an isosceles triangle

hypotenuse is AB .

we know that AC=BC

By using Pythagoras theorem, ΔACB

AC²+BC²=AB²

AC²+AC²=AB² (as AC=BC)

2AC² = AB²

Hence proved.

7. In the given figure AD⊥BC

∠ADC = ∠ ADB = 90°

As ΔADB is right angled

using pythagoras theorem,

AB² = (AD)² + (BD)² →(1)

As Δ ADC is right angled

using pythagoras theorem

AC² = (AD)² + (CD)² →(2)

By substracting (1) and (2),we get

AB² - AC² = (AD² + BD² ) - (AD² + CD²)

AB² - AC² = AD² + BC² - AD² - CD²

AB² - AC² = BD²- CD²

AB² + CD² = BD² + AC²

Hence proved.

Hope u get it.

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