Question

answer the question please as soon as possible

Answer 1

let side of first square be = X
and other square side be = y
now given,.
perimeters difference
4x-4y= 20
4(x-y) =20
x-y= 5
then X= 5+ y
now sum of areas of squares
x^2+y^2= 625
(5+y)^2. + y^2=. 625. putting x= 5+ y
25+10y +y^2 + y^2=. 625
2y^2 +10 y +25-625=0
2y^2 +10y + -600=0
2(y^2 +5y -300) =0
y^2 +5y -300=0
y^2+20y-15y - 300
y(y+ 20) -15(y+20)
(y+20)(y-15)

thus y= 15 and -20(not possible)

side of second square= 15cm
and side of first square= X= 5+y
X= 5+15= 20 cm
so X= 20cm
and y=15cm