Question

answer the question... plz​

Answer 1

Answer:

(5/2), 2

Step-by-step explanation:

Let the inner radius be r₁ and the outer radius be r₂ and height = 14 m.

(i)

2πr₂h - 2πr₁h = 44

⇒ 2πh(r₂ - r₁) = 44

⇒ 2 * (22/7) * 14(r₂ - r₁) = 44

⇒ (r₂ - r₁) = (44 * 7)/2 * 22 * 14

⇒ (r₂ - r₁) = 1/2

(ii)

Given that Petrol storage tank is made of 99 cm³.

⇒ πh(r₂² - r₁²) = 99

⇒ (22/7) * 14(r₂² - r₁²) = 99

⇒ 44 *  (r₂ + r₁)(r₂ - r₁) = 99

⇒ (r₂ + r₁) = 9/2

Now,

On solving (i) & (ii), we get

r₂ - r₁ = (1/2)

r₂ + r₁ = 9/2

---------------------

2r₂ = 5

r₂ = 5/2

Substitute r₂ = (5/2) in (i), we get

⇒ r₂ - r₁ = 1/2

⇒ (5/2) - r₁ = 1/2

⇒ r₁ = 2

Therefore:

Outer radius = (5/2) cm

Inner radius = 2 cm.

Hope it helps!

Answer 2

r= inner radius 

R= outer radius 

h= height of the metallic pipe = 14 cm

Difference between the Curved surface area of the outer cylinder and Curved surface area of the inner cylinder  = 2πRh - 2πrh.

Given: 

difference between the outside and inside curved surface area of cylinder= 44 cm2 .

so, 

2πh( R - r) = 44

2 x 22/ 7 x 14 ( R - r) = 44

R - r = 1 / 2 

= 0.5

Given:

the pipe is made up of metal= 99 cm³

Volume of cylindrical metallic pipe = πR²h - πr²h.

so, 

22/7 x 14 (R² - r²) = 99 

44(R² - r²) = 99

(R² - r²) = 9 / 4 

R²-r²= 2.25

( R - r)(R + r)  = 2.25

(0.5)(R + r) = 2.25

R + r = 2.25 / 0.5 

R + r  = 4.5

Adding up both the values we get

2R = 4.5 + 0.5 = 5

R = 2.5 cm and r  = 2 cm