Math, asked by ydtodkar25, 11 months ago

Answer the question plz ​

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Answered by rahman786khalilu
0

SecA+tanA=p

(sacA-tanA)(secA+tanA)=1

secA-tanA=1/p

secA+tanA=p

2secA=p+1/p

secA=p^2+1/2p

cosA=2p/1+p^2

sin^2A=1-4p^2/(p^2+1)^2

sinA=p^2-1/p^2+1

I took theta as A

hope it helps


ydtodkar25: How you take 2sec A= p+1/p???
rahman786khalilu: by adding tanA get cancelled so,we get
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