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The construction you have done is correct. The only thing you need to use is 'Converse of Mid-point Theorem' which says,
"Line drawn through the Mid-point of one side parallel to other bisects the third side".
So in triangle RQM,
DN || QM (Construction)
And D is the mid-point of QR (Given)
So from Converse of Mid-point theorem,
N is the mid-point of RM or MN = RN (1)
In triangle PDN,
TM || DN (as QM || DN and TM is a part of QM)
And T is the mid-point of PD (Given)
So From Converse of Mid-point theorem,
M is mid-point of PN or PM = MN (2)
From (1) and (2),
PM=MN=NR
As PM + MN + NR = PR,
3PM=PR
or
PM/PR = 1/3
"Line drawn through the Mid-point of one side parallel to other bisects the third side".
So in triangle RQM,
DN || QM (Construction)
And D is the mid-point of QR (Given)
So from Converse of Mid-point theorem,
N is the mid-point of RM or MN = RN (1)
In triangle PDN,
TM || DN (as QM || DN and TM is a part of QM)
And T is the mid-point of PD (Given)
So From Converse of Mid-point theorem,
M is mid-point of PN or PM = MN (2)
From (1) and (2),
PM=MN=NR
As PM + MN + NR = PR,
3PM=PR
or
PM/PR = 1/3
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