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P and q is the point
p (1,0) and q (0,1)
Step-by-step explanation:
now
d= √( x1 -x2) +(y1- y2)
d = √ ( 1-0)^2 +(0-1)^2
= √(1)^2 +( -1)^2
= √ 1+ 1
= √2
so d = √2
Answered by
1
Step-by-step explanation:
P and q is the point
p (1,0) and q (0,1)
Step-by-step explanation:
now
d= V(x1-x2) +(y1- y2)
d=V (1-r2 +(0-1)2
(12 (-12
= V 1+ 1
= 2
so d = v2
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