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resistor having resistance of 15 20 and 10 are connected in parallel , what is the effective resistance in the circuit ?
Answers
Answered by
15
Answer:
let the effective resistance be R then
1/R = 1/15 + 1/20 + 1/10 = (4 + 3 +6)/60 =13/60
R = 60/13 Ans
Answered by
53
✬ Resistance = 4.615 ohms ✬
Explanation:
Given
- Resistances are 15 ohms , 20 ohms and 10 ohms.
- These are connected in parallel.
To Find:
- What is the effective resistance in the circuit ?
Solution: For resistance connected in parallel we know the formula is
★ 1/RP = 1/R1 + 1/R2 + 1/R3 ..... ★
He//re we have
- R1 = 15 ohms
- R2 = 20 ohms
- R3 = 10 ohms
Putting the value on the formula
1/RP = 1/15 + 1/20 + 1/10
1/RP = 4 + 3 + 6/60
1/RP = 13/60
60 = 13RP
60/13 = RP
4.615 ohms = RP
Hence, the effective resistance in the circuit is 4.615 ohms.
- Note : (RP is for Resistance in Parallel)
- S.I unit of resistance is ohm metre.
amitkumar44481:
Great :-)
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