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Let the Number of Boys in the Tea party be : B
Let the Number of Girls in the Tea party be : G
Given : Nine friends had a Tea party
Number of Boys + Number of Girls should be equal to 9
B + G = 9
G = 9 - B
Given : Cost per cup of Coffee in rupees is numerically 2 less than the number of Girls
Cost per cup of Coffee = (G - 2) rupees
Given : All Boys took only Coffee
Total Number of Boys = Total Number of Coffee's
Total number of Coffee's = B
Total Expenses of the Boys on Coffee = B(G - 2) rupees
Given : Cost per cup of Tea in rupees is numerically 2 less than the number of Boys
Cost per cup of Tea = (B - 2) rupees
Given : All Girls took only Tea
Total Number of Girls = Total Number of Tea's
Total number of Tea's = 9 - B
Total Expenses of the Girls on Tea = (B - 2)(9 - B) rupees
Given - Ratio of the total expenses of the Boys and Girls is 5 : 6
6B(7 - B) = 5(B - 2)(9 - B)
42B - 6B² = 5[9B - B² - 18 + 2B]
42B - 6B² = 5[-B² + 11B - 18]
42B - 6B² = -5B² + 55B - 90
6B² - 5B² + 55B - 42B - 90 = 0
B² + 13B - 90 = 0
B² + 18B - 5B - 90 = 0
B(B + 18) - 5(B + 18) = 0
(B + 18)(B - 5) = 0
B = -18 (or) B = 5
As Number of Boys in the Tea Party cannot be a Negative Number
B ≠ -18
B = 5
Total Number of Boys in the Tea party (B) = 5
Total Number of Girls in the Tea party (G) = 4
We found that : Cost of each Coffee = (G - 2) rupees
Cost of each Coffee = (4 - 2) Rs.
Cost of each Coffee = 2 Rs.
Answer : Option (1)
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