Question

answer the question
$if \: tan \: a = \frac{12}{5} \: find \: \frac{1 + sin \: a}{1 - sin \: a}$
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Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$\tan(a) = \frac{12}{5} \\ \: \frac{p}{b} = \frac{12}{5} \\ hence \: {h}^{2} = {12}^{2} + {5}^{2} \\ h = \sqrt{144 + 25} \\ = \sqrt{169} = 13 \\ now \: \\ \sin(a) = \frac{p}{h} = \frac{12}{13} \\ \frac{1 + \sin(a) }{ 1 - \sin(a) } \\ = \frac{1 + \frac{12}{13} }{1 - \frac{12}{13} } \\ = \frac{ \frac{25}{13} }{ \frac{1}{13} } \\ = \frac{25}{13} \times \frac{13}{1} \\ = 25$