Question

answer the question which is in attachment​

Answer 1

Answer:

HOPE ABOVE ATTACHMENT HELPS YOU......

Answer 2

ANSWER :

The velocity with which the gun recoil is$\sf - 1 \: m/s^{2}−1m/s$

2

The force exerted on gun man due to recoil of the gun is 1000 N.

GIVEN :

Mass of gun = 3 kg.

Mass of bullet = 30 g.

Time, t = 0.003 sec.

Velocity, v = 100 m/s.

TO CALCULATE :

The velocity with which the gun recoils.

The force exerted by the gun man due to recoil of the gun.

FORMULA :

$\sf Force \: = \: \dfrac {\Delta p}{\Delta t}$Force=

Δt

Δp

SOLUTION :........

Net force on gun and bullet, system is zero.

$\hookrightarrow [tex]\sf 3 \: \times \: v \: (30 \times 10^{-3}) \: \times 100 \: = \:$ 0↪3×v(30×10

−3

)×100=0

$\hookrightarrow \sf 3v \: = \: - (30 \: \times \: 10^{-1}$↪3v=−(30×10

−1

$\therefore \boxed{\sf V \: = \: - 1 \: m/s^{2}}∴ </p><p>V=−1m/s$

2

....

$\bold\red{Force \: = \: \dfrac {\Delta p}{\Delta t}}$Force=

Δt

Δp

$\hookrightarrow↪ \sf \dfrac {m(v \: - \: 0)}{0.003}$

0.003

m(v−0)

$\hookrightarrow↪ \sf \dfrac {3 \: \times \: 1}{0.003}$

0.003

3×1

$\therefore \boxed{\sf F \: = \: 1000 \: N}$∴

F=1000N..