Question

answer the question which is in the attachment

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Answer 1

$\mathcal{\large{\fbox{\purple{Number\:System\:Test:-}}}}$

$\mathtt{\large{\underline {\red{Number\:System:-}}}}$

1. (1234)10

= 1 × 10³ + 2× 10² + 3 × 10¹ + 4 × 10°

= 1000 + 200 + 30 + 4

= 1207

2.(1010)2

= 1 × 10³ + 0 × 10² + 1 × 10¹ + 0 × 10°

= 1000+0+10+0

=1010

3.(357)8

= 3×8² + 5×8¹ + 7×8°

= 3×64 + 40 + 7

=192+40+7

=239

4.(560)8

= 5×8² + 6×8¹ + 0×8°

= 5×64+6×8+0

= 320 + 48

= 368

5.(50)16

= 5×16¹ + 0×16°

= 80 + 0

= 80

$\mathtt{\large{\underline {\red{Number\:System\:Conversion:-}}}}$

1.)Decimal to Binary (78) = ()2

➡ (78) = (x)2

➡ x.2¹+x.2° =78

➡ 2x + x = 78

➡ 3x = 78

➡ x = 78/3

➡ x= 29

2. Decimal to Octal (45)= ()8

➡ (45) = (x)8

➡ x.8¹+x.8° =45

➡ 8x + x = 45

➡9x = 45

➡ x = 45/9

➡ x= 5

3. Decimal to Hexadecimal (55) = ()16

➡ (55) = (x)16

➡ x.16¹+x.16° =55

➡ 16x + x = 55

➡ 17x = 55

➡ x = 55/17

➡ x= 3.25 ≈ 4

➡ x = 4

______________________________________

Answer 2

Answer:

NumberSystem:−

1. (1234)10

= 1 × 10³ + 2× 10² + 3 × 10¹ + 4 × 10°

= 1000 + 200 + 30 + 4

= 1207

2.(1010)2

= 1 × 10³ + 0 × 10² + 1 × 10¹ + 0 × 10°

= 1000+0+10+0

=1010

3.(357)8

= 3×8² + 5×8¹ + 7×8°

= 3×64 + 40 + 7

=192+40+7

=239

4.(560)8

= 5×8² + 6×8¹ + 0×8°

= 5×64+6×8+0

= 320 + 48

= 368

5.(50)16

= 5×16¹ + 0×16°

= 80 + 0

= 80

\mathtt{\large{\underline {\red{Number\:System\:Conversion:-}}}}

NumberSystemConversion:−

1.)Decimal to Binary (78) = ()2

➡ (78) = (x)2

➡ x.2¹+x.2° =78

➡ 2x + x = 78

➡ 3x = 78

➡ x = 78/3

➡ x= 29

2. Decimal to Octal (45)= ()8

➡ (45) = (x)8

➡ x.8¹+x.8° =45

➡ 8x + x = 45

➡9x = 45

➡ x = 45/9

➡ x= 5

3. Decimal to Hexadecimal (55) = ()16

➡ (55) = (x)16

➡ x.16¹+x.16° =55

➡ 16x + x = 55

➡ 17x = 55

➡ x = 55/17

➡ x= 3.25 ≈ 4

➡ x = 4