Math, asked by Anonymous, 1 year ago

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Answers

Answered by Anonymous
20

Answer:

I hope it is helpful........

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Answered by Nereida
82

\huge\star{\red{\underline{\mathfrak{Answer}}}}

Step 1:- Cross multiplication

(2 {x}^{3} - 3 {x}^{2}  + x + 1) \times\\\\ (3 {x}^{3}  -  {x}^{2}  - 5x + 13) =\\\\ (2 {x}^{3}  - 3 {x}^{2}  - x - 1) \times \\\\(3 {x}^{3}  -  {x}^{2}  + 5x  - 13 )

Step 2:- Multiply the equations

(6 {x}^{6}  - 2 {x}^{5}  - 10{x}^{4}  + 26 {x}^{3}\\\\  - 9 {x}^{2}  + 3 {x}^{2}  + 15 {x}^{3}  - 39 {x}^{2}  \\\\+ 3 {x}^{4}  -  {x}^{3}  - 5 {x}^{2}  + 13x \\\\+ 3 {x}^{3}  -  {x}^{2}  - 5x + 13) \\\\= (6 {x}^{6}  - 2 {x}^{5}  + 10 {x}^{4} \\\\ - 26 {x}^{3}  - 9 {x}^{4}  + 3 {x}^{4}  \\\\- 15 {x}^{3}  + 39 {x}^{2}  - 3 {x}^{4}\\\\  +  {x}^{3}  - 5 {x}^{2}  + 13x - 3 {x}^{3} \\\\ +  {x}^{2}  - 5x + 13)

Step 3:- Cut the terms of the equation on both sides of it which has same sign,coefficient and the variable with same power.

So, the equation now shortens.

( - 10 {x}^{4}  + 26 {x}^{3}  + 15 {x}^{3}  - 39 {x}^{2}\\\\  + 3 {x}^{4}  -  {x}^{3}  + 3 {x}^{3}  -  {x}^{2})\\\\  = (10 {x}^{4}  - 26 {x}^{3}  - 15 {x}^{3}  + 39 {x}^{2}  \\\\- 3 {x}^{4}  +  {x}^{3}  - 3 {x}^{3}  +  {x}^{2} )

Step 4:- Shift the terms on the right side to left. This helps in calculating the answer easily.

( - 10 {x}^{4}  + 3 {x}^{4}  - 10 {x}^{4}  + 3{x}^{4} ) \\\\+ (26 {x}^{3}  + 15 {x}^{3}  -   {x}^{3} \\\\ + 3 {x}^{3}  + 26 {x}^{3}  + 15 {x}^{3}  \\\\-  {x}^{3}  + 3 {x}^{3} ) + ( - 39 {x}^{2}  -  \\\\{x}^{2}  - 39 {x}^{2}  -  {x}^{2} ) = 0

I have also arranged the terms according to their power.

This way you can calculate easily.

Step 5:-Calculate the coefficients of the variable with same power.

 - 14 {x}^{4}  + 86 {x}^{3}  - 80 {x}^{2}  = 0

Step 6:-If you find any common factor of all the three terms, then remove it for easy calculation.

 - 2 {x}^{2} (7 {x}^{2}   - 43x + 40) = 0

Step 7:-Now, move the common term on right side.

The term will be divide 0, so the answer will be 0.

 (7 {x}^{2}   - 43x + 40) = 0

Step 8:-Now take out the value of x.

 (7 {x}^{2}   - 35x -8x + 40) = 0

 (7x(x-5)  - 8 (x-5)) = 0

 (7x-8)(x-5) = 0

Therefore,

(7x-8)=0

x=(8/7)

and

(x-5)=0

x=5

So, The values of x are:-

\huge\boxed{x=(8/7),(5)}

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