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SOLUTION
Congruency of ∆
In ∆ABC & ∆DEC
∠ACB= ∠CDE (Alternate angle)
∠BAC= ∠DEC (Alternate angle)
∠BAC = ∠CED(opposite angle)
So, ∆ ABC ∆DEC
Hence,
BC= CD (CPCT)
Now,
2x-4= 14
=) 2x= 14+4
=) 2x=18
=) x= 18/2
=) x= 9
3y+5= 20
=) 3y= 20-5
=) 3y= 15
=) y= 15/3
=) y= 5
hope it helps ☺️
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