ANSWER THE QUESTION....
With detailed solution .
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Hey dear here is your answer!!!!!!
Hope it helps u dear...❣️❣️⭐⭐
Hope it helps u dear...❣️❣️⭐⭐
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helpme10:
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i m in 11 and she too in 11
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ℌ℮¥¥Ѧ
LHS = Cos2x + Cos2(x+^/3) + Cos2(x-^/3)
= (1+cosx)1/2 + (1+cos(x+^/3))1/2 + (1+cos(x-^/3)) 1/2
= 1/2 ( 1+cosx + 1 +Cos(x+^/3) + 1 + Cos(x-^/3) )
= 1/2 ( 3 + cosx + Cos( x + 60 ) + Cos( x - 60)
. = 1/2 ( 3 + Cosx + 2 cosx cos120)
= 1/2 ( 3 + cosx + 2 cosx . -1/2) (since cos 120 = -1/2)
= 1/2 ( 3 + cosx - cosx)
= 3/2 = RHS
here , ^ means "pi"
ℌ◎℘℮ ї† ℌ℮ℓ℘﹩
LHS = Cos2x + Cos2(x+^/3) + Cos2(x-^/3)
= (1+cosx)1/2 + (1+cos(x+^/3))1/2 + (1+cos(x-^/3)) 1/2
= 1/2 ( 1+cosx + 1 +Cos(x+^/3) + 1 + Cos(x-^/3) )
= 1/2 ( 3 + cosx + Cos( x + 60 ) + Cos( x - 60)
. = 1/2 ( 3 + Cosx + 2 cosx cos120)
= 1/2 ( 3 + cosx + 2 cosx . -1/2) (since cos 120 = -1/2)
= 1/2 ( 3 + cosx - cosx)
= 3/2 = RHS
here , ^ means "pi"
ℌ◎℘℮ ї† ℌ℮ℓ℘﹩
But u didn't given the whole answer.
Hmm.... Now it is correct.
U can use simple font style as this one is quite unreadable.
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