Question

Answer the question with good explanation ​

Answer 1

Answer:

0.002 s is  the time interval between successive compressions from the source.

Explanation:

Given :

Sound - 500Hz.

Distance - 450m.

To Find :

The time interval between successive compressions from the source.

Solution :

We know that :

$\bigstar\;\boxed{\sf v =\lambda V }}$

So,

$\sf\\ \\\implies 500\times 450\\ \\ \\ \implies 22500\;m/s.$

Now,

We know :

$\sf \implies v = \dfrac{\lambda}{T}$

Therefore,

$\sf\\ \\\implies T = \dfrac{\lambda}{v}\\ \\ \\ \implies T = \dfrac{450}{22500}\\ \\ \\\implies T = \dfrac{1}{500}\\ \\ \\\implies T = 0.002\;Seconds$

∴ 0.002 s is  the time interval between successive compressions from the source.

Remember :

The time interval between successive compressions is equal to the time period of the wave.

That time period is the reciprocal of the frequency of the wave.

Answer 2

Answer:T/frequency

1/500

0.002s

Explanation: the time intervel between successive compressions is equal to the time period of Wave. This time is reciprocal of the frequency of the Wave.