Question

❤❤ANSWER THE QUESTION WITH QUALITY :)
CLASS 11.
PHYSICS

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Answer 1

Answer:

Solution :

The strain in the wire △ll=2.0mm2.0m=10−3△ll=2.0mm2.0m=10-3

The stress in the wire =Y×Stra∈=Y×Stra∈

=2.0×101Nm−2×10−3=2.0×108Nm−2=2.0×101Nm-2×10-3=2.0×108Nm-2

The volume of the wire =(4×10−6m2)×(2.0m)=(4×10-6m2)×(2.0m)

=8.0×106−6m3=8.0×106-6m3

the elastic potential energy stored

=12×stress×stra∈×volume=12×stress×stra∈×volume

=12×2.0×108Nm−2×8.0×10−6m3=12×2.0×108Nm-2×8.0×10-6m3

=0.8J

Answer 2

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