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Let the initial volume of sphere be "r"¹ and the initial volume be " V"¹
So, the initial volume of sphere, V¹=4/3πr³.It is given that, the radius of sphere is increased by 100%
The new radius, r²=r¹+(100%of r¹) =2r¹
Now,
The new volume of the sphere,
V²=4/3πr²
V²=4/3π(2r¹) ³
V²=4/3π×(8×r¹) ³
V²=8×V¹
Thus,
The volume of corresponding sphere is increased by,
{(V²-V¹) /V¹}×100
{8(V¹-V¹) /V¹}×100
{7V¹/V¹}×100
7×100
700% Ans.
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