Question

Answer the questions
(1) A man goes 24 m due west and then 10 m due north. How far is he from the starting point?​

Answer 1

Answer:

☞Given :

OA=24 cm AB=10 m

Let OB=x m

In right angle △OAB

☞To Find:

How far is he from the starting point

☞Solution:

By using pythagoras theorem

$OB2 {}^{2} =OA {}^{2} +AB {}^{2} \\ </p><p></p><p>OB {}^{2} =(10) {}^{2} +(24) {}^{2} </p><p> \\ </p><p>OB {}^{2} =100+576</p><p> \\ </p><p>OB {}^{2} =676</p><p> \\ </p><p>OB=26m$