Question

answer the questions​

Answer 1

AnswEr:-

$\huge \red{Hey \: Mate}$

$\huge \blue{Here's \: Your \: Answer \: in \: the \: Attachment}$

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Answer 2

$\dfrac {2x}{x^2-4}+\dfrac {1}{x^2+3x+2}\\\\\\=\dfrac {2x}{(x-2)(x+2)}+\dfrac {1}{(x+1)(x+2)}\\\\\\=\dfrac {1}{x+2}\left [\dfrac {2x}{x-2}+\dfrac {1}{x+1}\right]\\\\\\\dfrac {1}{x+2}\left [\dfrac {2x(x+1)+x-2}{(x+1)(x-2)}\right]\\\\\\=\dfrac {1}{x+2}\left [\dfrac {2x^2+3x-2}{(x+1)(x-2)}\right]\\\\\\=\dfrac {1}{x+2}\left [\dfrac {(x+2)(2x-1)}{(x+1)(x-2)}\right]\\\\\\=\dfrac {2x-1}{(x+1)(x-2)}\\\\\\=\dfrac {(x+1)+(x-2)}{(x+1)(x-2)}\\\\\\=\dfrac {1}{(x+1)}+\dfrac {1}{(x-2)},\quad x\neq-1;\ x\neq2$