Question

Answer the questions​

Answer 1

Explanation:

Hey dude here is your answer

so here initial velocity = 80 km/h = 200/9 m/s

final velocity = 60 km/h = 50/3 m/s

time = 5 sec

accelaration = ?

so. formulae of acceleration

final velocity – initial velocity /time

so 50/3 – 200/9 /5

so taking lcm of 3 and 9 we get

150 – 200/9/5

so answer = -10/9 m/s²

ii---- final velocity = 40 km /h = 100/9 m/s

initial velocity = om/ s. ( starting from rest

time = 10 min = 600 sec

so acceleration = 100/9 – 0/600

answer = 1/54 m/s²

Bhai brainliest banadena itna lambs method kiya hai

Answer 2

Question :

A bus decreases it speed from 80 Km/h to 60 Km/h in 5 seconds. Find the acceleration of the bus

Answer :

Initial velocity ( u ) = 80 Km / h = 80 × 5 / 18 = 22.2 m/s

Final velocity ( v ) = 60 Km / h = 60 × 5 / 18 = 16.6 m/s

Time ( t ) = 5 seconds

Acceleration ( a ) = ?

We know that

=> a = ( v - u) / 5

=> a = ( 16.6 - 22.2 ) / 5

=> a = - 5.6 / 5

=> a = - 1.12

Therefore acceleration of the bus is - 1.12 m/s².

$\rule{200}1.5$

Question :

A train starting from a railway station and moving with uniform acceleration attains a speed 40 Km/h in 10 minutes. Find its acceleration.

Answer :

Train starts from rest

So, Initial velocity ( u) = 0 Km / h

Final velocity ( v ) = 40 Km/h

Time ( t ) = 10 min = 10 / 60 = 1 / 6 hrs

Acceleration ( a) = ?

=> a = ( v - u ) / t

=> a = ( 40 - 0 ) / ( 1 / 6 )

=> a = 40 × 6

=> a = 240 Km/h² = 240 / 1296 = 0.0185 m/s²

Therefore the acceleration of the train is 240 Km/h² or 0.0185 m/s²