Math, asked by chaviLOVER, 9 months ago

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Answered by Anonymous

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ʟʜs=

ᶜᵒᵗ 4ˣ( ˢⁱⁿ5ˣ+ˢⁱⁿ 3ˣ)=ᶜᵒᵗ 4 ˣ[2 ˢⁱⁿ(5ˣ+3ˣ/2)/ᶜᵒˢ (5ˣ-3ˣ/2)]

=ᶜᵒᵗ 4ˣ(2 ˢⁱⁿ4ˣ.ᶜᵒˢ ˣ)

=2 ᶜᵒˢ 4ˣ/ˢⁱⁿ4ˣ . ˢⁱⁿ 4ˣ.ᶜᵒˢ ˣ

=2ᶜᵒˢ 4ˣ.ᶜᵒˢ ˣ..(ⁱ)

ʀʜs =

ᶜᵒᵗ ˣ(ˢⁱⁿ 5ˣ-ˢⁱⁿ 3ˣ)

=ᶜᵒᵗ ˣ [2 ᶜᵒˢ (5ˣ+3ˣ/2)ˢⁱⁿ(5ˣ-3ˣ/2)]

=ᶜᵒᵗ ˣ(2 ᶜᵒˢ 4ˣ.ˢⁱⁿ ˣ)

=2ᶜᵒˢ ˣ /ˢⁱⁿ ˣ.ᶜᵒˢ 4ˣ.ˢⁱⁿˣ

=2 ᶜᵒˢ ˣ.ᶜᵒˢ 4ˣ..(ⁱⁱ)

ғʳᵒᵐ ᵉᵠ (ɪ) ᵃⁿᵈ (ⁱⁱ) ʟʜs =ʀʜs

[ғᵒʳᵐᵘˡᵃ ˢⁱⁿ ᵃ+ˢⁱⁿ ᵇ=2 ˢⁱⁿ(ᵃ+ᵇ/2).ᶜᵒˢ (ᵃ-ᵇ)] ᵃⁿᵈ ˢⁱⁿ ᵃ- ˢⁱⁿ ᵇ =2 ᶜᵒˢ (ᵃ+ᵇ/2).ˢⁱⁿ(ᵃ-ᵇ/2)]

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Answered by SwaggerGabru

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