Math, asked by sunitasuthar63, 1 month ago

answer the questions​

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Answers

Answered by boysecert1
0

Answer:

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Answered by singhsahilsanskar
0

Step-by-step explanation:

Given : 7(x−2y)

2

−25(x−2y)+12

Let us consider x−2y=z

So we get,

=7z

2

−25z+12

We can further write it as

=7z

2

−21z−4z+12

By taking out the common terms

=7z(z−3)−4(z−3)

=(7z−4)(z−3)

Let us replace z by x−2y

So we get

7(x−2y)

2

−25(x−2y)+12

Then,

=(7(x−2y)−4)((x−2y)−3)

=(7x−14y−4)(x−2y−3)

So, 7(x−2y)

2

−25(x−2y)+12 =(7x−14y−4)(x−2y−3)

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