Question

answer the questions​

Answer 1

Answer:

In Δ APB and Δ CQD

AB = CQ (∵opposite sides of a parallelogram are equal)

∠APB = ∠CDQ = 90°

∠ABP = ∠ CQD (∵ interior alternate angles)

∴ By AAS congruency, Δ APB ≅ Δ CQD

Hence Proved

AP = CQ (∵ corresponding parts of congruent triangles are equal)