Question

Answer the questions above in the attachment !​

Answer 1

Step-by-step explanation:

To prove= triangle ABC is an isosceles

As

BD=DC(AD is perpendicular bisector of BC)

AD=AD(Common)

Angle ABD= Angle ADC = 90(perpendicular)

BY SAS CONGRUENCE RULE:-

Triangle ADB is congruent to triangle ADC

BY CPCT, AB=AC

Hope it helps!

Plz Mark as brainliest

Answer 2

$\huge{\boxed{\mathfrak\pink{answer}}}$

Let the sign for congruence be '='.

In ∆ADB and ∆ADC,

seg AD = seg AD ...(Common side)

Angle ADB = Angle ADC ...(Both 90 degrees)

Angle BAD = Angle CAD ...(seg AD bisects angle BAC - Given)

Thus, ∆ADB = ∆ADC ...(i) (SAA Test of congruence of triangles)

Thus, from equation (i), we can conclude,

seg AB = seg AC ...(ii) (Congruent sides of congruent triangles)

Now, in ∆ABC,

side AB = side AC ...[From (ii)]

Thus, ∆ABC is an isosceles triangle in which AB = AC.

Hope this helps.....