Physics, asked by akshatsingh9097, 2 months ago

answer the questions appropriately​

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Answered by FFdevansh
1

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number \: of \: oscillation = 20

total \: time \: taken \: for \: 20 \: oscillation

 = 25 \: sec

time \: period = 25/20 = 1.25 \: sec

least \: count \: of \: watch = 0.2 \: sec

the \: measurement \: of \: time \: period \: 1.25 \: sec

the \: measuring \: watch \: can \: measure

upto \: 0.2s \: thus \: the \: watch \: can \:

measure \: 0.2s \: but \: the \: uncertaimly

remains \: the \: 0.05 \:  \: s.

1.25 \: s \:   = 1.2 + 0.05

thus \: error \:  = 0.05 \: sec

percentage \: error

 = (0.05/1.25) \times 100 = 4\%

\large\mathcal\blue{HOPE \: IT'S \: HELPS \: YOU}

\huge\mathfrak\red{@FFdevansh}

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