answer the questions given in the photo ..any three
Answers
Answer:
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Answer:
1) ii) y²+1/y = 1
y³ + 1 = y
y³-y+1 = 0
hence, this polynomial is not quadratic polynomial because highest degree of polynomial is 3
iii) A.P — a1 = 10
a2 = a+d = 10+5 = 15
a3 = a+2d = 10+2×5 = 20
A.P — 10,15, 20
iii)m(4+3m)= -5
4m + 3m² = -5
3m²+4m +5 = 0
2) ii) x = 3
kx²-10x+3 = 0
k(3)² - 10(3) + 3 = 0
9k - 30 + 3 = 0
9k -27 = 0
9k = 27
k = 3
iii) a = 12 , d = 16-12= 4
a24 = a+ 23d
= 12 + 23×4
= 12 + 92
= 104
3) let present age be x
(x-2)(x+3) = 84
x(x+3)-2(x+3) = 84
x² + 3x - 2x - 6 = 84
x² + x -6 -84 = 0
x² + x - 90 = 0
x² + 10x - 9x - 90 = 0
x(x + 10) - 9(x + 10) = 0
(x+ 10) (x-9) = 0
x = -10, x = 9
hence present age be 9
age can't negative