Question

Answer the questions please fast​

Answer 1

Answer:

Ashima was 12 yeared two years ago.

Step-by-step explanation:

According to the first given condition that is, Sunita is twice as old as Ashima. Given, if six years is subtracted from Ashima's age and four years added to Sunita's age, then Sunita will be four times that of Ashima's age. Thus, Ashima's present age is 14 years.

Answer 2

Step-by-step explanation:

Let Ashimas's present age = A years

According to the first given condition i.e., Sunita

is twice as old as Ashima.

Therefore, S = 2A...(1)

Given, if six years is subtracted from Ashima's age and four years added to Sunita's age, then Sunita will be four times that of Ashima's age.

Therefore,

4x (4-6) S +4

⇒ 44-24 = S +4

⇒ 4A-S=28 ...(ii)

Now, putting value of S from equation (i) in

equation (ii), we get

4A-2A = 28

⇒ 2A = 28 A = 14

Thus, Ashima's present age is 14 years.

Putting value of A in equation (i), we have

S=2x1428 years

Sunita's present age is 28 years.

Ashima's age 2 years ago = (14 - 2) years = 12

years

Sunita's age 2 years ago = (28 - 2) years = 26

years

Sum of Ashima's age and Sunita's age two years

ago = (12+26) years = 38 years So, the correct answer is "38 years".