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In ∆ABC exterior angle property,
ACD = A+B
C = 40+30
C= 70°
now x= C+D
x= 70+50
x= 120°
ACD = A+B
C = 40+30
C= 70°
now x= C+D
x= 70+50
x= 120°
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A + B + C = 180
30 + 40 + C = 180
70 + C = 180
C = 180 - 70 = 110
Thus, C = 110
C + D + E = 180
70 + 50 + E = 180
120 + E = 180
E = 180 - 120
E = 60
E + X = 180 ( linear pair)
60 + X = 180
X = 180 - 60
X = 120
30 + 40 + C = 180
70 + C = 180
C = 180 - 70 = 110
Thus, C = 110
C + D + E = 180
70 + 50 + E = 180
120 + E = 180
E = 180 - 120
E = 60
E + X = 180 ( linear pair)
60 + X = 180
X = 180 - 60
X = 120
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