answer the rounded problem
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let numbers be x and another one will be x+2.
A.T.Q,
x^2+(x+2)^2=580
x^2+x^2+4x+4-580=0
2x^2+4x-576=0
Divide by 2
x^2+2x-288
Using quad. equation,
D=b^2-4ac
=4-5(-288)
=4+1152
=1156
√D=34
zeroes=-2-34/2=-36/2=-18
-2+34/2=32/2=16
negative would be ignored.
numbers are 16 and 18
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