Question

answer the second question

Answer 1

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Answer 2

Here is your answer

$x {}^{2} + 1 = 0 \\ x {}^{2} = - 1 \\ x = \sqrt{ - 1} \\ as \: \sqrt{ - 1} \: has \: negative \: numbe \: so \: it \: does \: not \: have \: any \: zeros$
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