Question

Answer the sum 9408 by prime factorization method

Answer 1

Answer:

Square root of 9408 is 56 \sqrt{3}56

3

Step-by-step explanation:

Number = 9408

We are supposed to find square root of 9408 by prime factorization method

So,

2 | 9408

2 | 4704

2 | 2352

2 | 1176

2 | 588

2 | 294

7 | 147

7 | 21

3 | 3

| 1

9408= 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 39408=2×2×2×2×2×2×7×7×3

\sqrt{9408}=\sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 7 \times 7 \times 3}

9408

=

2×2×2×2×2×2×7×7×3

\sqrt{9408}=2 \times 2 \times 2 \times 7 \times \sqrt{3}

9408

=2×2×2×7×

3

\sqrt{9408}=56 \sqrt{3}

9408

=56

3

Hence square root of 9408 is 56 \sqrt{3}56

3

Step-by-step explanation:

Mark as brainliest