Answer the third one
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As it is given that the triangles are similar, the corresponding sides are proportional i.e,
AB/CD=AM/CM=MB/MD
Substituting the given values we get,
y/z=x/MD
MD=(x×z) /y
=xz/y
Hope you like the answer
AB/CD=AM/CM=MB/MD
Substituting the given values we get,
y/z=x/MD
MD=(x×z) /y
=xz/y
Hope you like the answer
Answered by
0
answer
DM=
|AMB=|CMD
AB//CD
MB/MC=MA/MD (Basic proportionality theorem)
x/z=DM/y
DM =xy/z
DM=
|AMB=|CMD
AB//CD
MB/MC=MA/MD (Basic proportionality theorem)
x/z=DM/y
DM =xy/z
MadhavNNambi:
bro, your is good, but basic proportionality theorem has no role in solving the question
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