Question

answer the two question
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Answer 1

consider triangle SRQ, TQR

QS=TR (as PS=PT)

QR=QR (common )

90=<QSR =<RTQ (angle opp to equal sides are equal)_1

by RHS criteria SRQ=TQR

by CPCT, QT=RS

consider triangle BCD, BCE

BD=CE (given )

BC=BC

<CDB=<CEB (by 1)

by SAS criteria BCD=BCE

by CPCT BE=CD

Answer 2

Step-by-step explanation:

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