Question

answer the up given photo​

Answer 1

Answer:

sin theta=3/5=p/h

p=3x , h=5x

to find base (by pythagoras theorem)

h^2=p^2+b^2

(5)^2=(3)^2+b^2

25=9+b^2

25-9=b^2

16=b^2

4=b

A.T.Q

SECtheta =h/b

=5x/4x

=5/4

TANtheta=p/b

=3x/4x

3/4

sectheta-tan theta÷sectheta+tan theta

5/4-3/4÷5/4+3/4

2/4÷8/4

1/2×1/2

1/4

Answer 2

Answer:

your answer attached in the photo