answer the up given photo
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sin theta=3/5=p/h
p=3x , h=5x
to find base (by pythagoras theorem)
h^2=p^2+b^2
(5)^2=(3)^2+b^2
25=9+b^2
25-9=b^2
16=b^2
4=b
A.T.Q
SECtheta =h/b
=5x/4x
=5/4
TANtheta=p/b
=3x/4x
3/4
sectheta-tan theta÷sectheta+tan theta
5/4-3/4÷5/4+3/4
2/4÷8/4
1/2×1/2
1/4
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your answer attached in the photo
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