Math, asked by muskan10453, 1 month ago

Answer the value of given question...​

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Answered by MysticSohamS
1

Answer:

hey here is your solution

pls mark it as brainliest

Step-by-step explanation:

to \: find =   \\  \frac{2.sin \:θ.cos \:θ - cos \: θ  }{1 - sin \: θ + sin {}^{2}  \:θ - cos {}^{2} \:  θ }  \\  \\  =  \frac{2.sin \:θ.cos \:  θ - cos \:θ }{1 - sin \: θ + sin {}^{2} θ - cos {}^{2} \:θ  }  \\  \\  =  \frac{cos \:θ(2.sin \: θ - 1)}{1 - sin \:θ + sin {}^{2}  \: θ - (1 - sin {}^{2}  θ) }  \\  \\  =  \frac{cos \:θ(2.sin \: θ - 1) }{1 - sin \:θ  + sin {}^{2}  \: θ -  1+sin {}^{2}   \: θ}  \\  \\  =  \frac{cos \:θ(2.sin \:  θ - 1)}{2sin {}^{2}θ - sin \: θ }  \\  \\  =  \frac{cos \:θ(2.sin \: θ - 1) }{sin \:θ(2.sin \: θ - 1)}  \\  \\  =  \frac{cos \:θ }{sin \:θ }  \\  \\  = cot \: θ

Answered by vrindhaushus
1

Answer:

will u pls unfollw me

pls

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