Math, asked by haritkshj, 24 days ago

answer these 5 questions with explanation correct and I will mark you brainliest

SCAMING WILL GET REPORTED

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Answers

Answered by TigerMan28
1

Answer:

1)

Let the number be in the form of 10x + y

A.T.Q.

x + y = 9. --------1

10x + y + 9 = 10y + x

10x - x + 9 = 10y - y

9x + 9 = 9y

x + 1 = y. ---------2

Putting y = x + 1 in equ.1

x + x + 1 = 9

2x + 1 = 9

2x = 8

x = 4

The number is 45.

2)

Let the numbers be x & y.

A.T.Q.

x + y = 5 ---------1

x^2 - y^2 = 5 ----------2

x - y = ?

Using equ. 1 & 2

x^2 - y^2 = 5 (x^2 - y^2 = (x + y)(x - y))

(x + y)(x - y) = 5

(5)(x - y) = 5

x - y = 1

3)

Let the numbers be in the form of x, x +1, x +2, x+3.

A.T.Q.

x + x + 1 + x + 2 + x + 3 = 166

4x + 6 = 166

4x = 160

x = 40

Therefore, the numbers are 40, 41, 42 & 43.

4)

x = x/2 + x/4 + 1200

x = 2x/4 + x/4 + 1200

x = 2x + x / 4 + 1200

x - 3x/4 = 1200

x/4 = 1200

x = 4800

5)

Perimeter = 2(l+b)

220 = 2(5y + 4 + 2y + 36)

110 = 7y + 40

7y = 70

y = 10

Plz mark me as the brainliast.

Answered by tennetiraj86
2

Step-by-step explanation:

Solutions :-

1)

Let the two digits of a number be X and Y

Let the digit at 10's place = X

Let the digit at 1's place = Y

The two digit number = 10X+Y

Given that

The sum of the digits = 9

=> X+Y = 9

=>X = 9-Y -------(1)

If 9 is added to the number the digits interchanged

=> 10X+Y +9 = 10Y+X

=> 10X+Y+9-10Y-X = 0

=>9X-9Y +9 = 0

=> 9(X-Y+1) = 0

=> X-Y+1 = 0

=>9-Y-Y+1 = 0

=>10-2Y = 0

=> 2Y = 10

=> Y = 10/2

=> Y = 5

Now

X = 9-5 = 4

Therefore the number = 45

2)

Let the two numbers be X and Y

Sum of the two numbers = 5

=> X+Y = 5-----(1)

Difference of their squares = 5

=> X²-Y² = 5

=> (X+Y)(X-Y) = 5

=> 5(X-Y) = 5

=> X-Y = 5/5

=> X-Y = 1

The difference of the two numbers = 1

3)

Let the four consecutive natural numbers are X,X+1,X+2,X+3

Their sum = X+X+1+X+2+X+3 = 4X+6

According to the given problem

Their sum = 166

=> 4X+6 = 166

=> 4X = 166-6

=>4X = 160

=>X = 160/4

=> X = 40

X+1 = 40+1 = 41

X+2 = 40+2 = 42

X+3 = 40+3 = 43

The four consecutive natural numbers are 40,41,42,43

4)

Given that

Money of a man = Rs. X

Money given to his wife = half of the money

= Rs. X/2

Money given to his son = 1/4th of the money

=>Rs. X/4

Money given to his daughter = Rs. 1200

Total money

=> (X/2)+(X/4)+1200 = X

=> (2X+X+4800/4 = X

=> (3X+4800)/4 = X

=> (3X+4800) = 4X

=>4X=3X+4800

=>4X-3X = 4800

=>X = 4800

=>X-4800 = 0 is the required equation

=> X = 4800

The money of the man = Rs. 4800

5)

Length of the rectangle = (5y+4) cm

Breadth of the rectangle = (2y+36) cm

Perimeter of a rectangle = 2(l+b) units

=>P = 2(5y+4+2y+36) cm

=> P = 2(7y+40) cm

=> P = 14y+80 cm

According to the given problem

The perimeter = 220 cm

=> 14y+80 = 220

=> 14y = 220-80

=>14y = 140

=> y = 140/14

=> y = 10 cm

Therefore, the value of y = 10 cm

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