Physics, asked by beautysophomore, 1 year ago

answer these :-
a) how much energy is transferred when 1g of boiling water at 100°c condenses to water at 100°c ?
b) how much energy is transferred when 1g of boiling water at 100°c cools to water at 0°c ?
c) how much energy is released or absorbed when 1g of water freezes to ice at 0°c ?
d) how much energy is released or absorbed when 1g of steam at 100°c turns to ice at 0°c ?
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please answer to every question and get 100 points
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Answers

Answered by Anonymous
10

❤️here is your answer my dear friend :-❤️

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a) when one gram of boiling water at 100°c condense to water at 100°c there is no change of temperature and the energy transfered is given by latent heat of vaporisation of water which is equal to 2260 joules

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b),c),d) answers can be seen in my attachments

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❤️thanks for your question akshaya❤️

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Attachments:

beautysophomore: thanks bhavana
beautysophomore: :-)
Answered by PushpeshPankaj
3

(a) The energy transferred when 1 gm of boiling water at 100C condenses to water at 100C is equal to the latent heat of vapourisation of water which is equal to 2260 Joule

(b) mass of water (m) = 1g

(b) mass of water (m) = 1ginitial temperature (T1) = 0 c

(b) mass of water (m) = 1ginitial temperature (T1) = 0 cFinal temperature (T2) = 100 c

(b) mass of water (m) = 1ginitial temperature (T1) = 0 cFinal temperature (T2) = 100 cspecific heat of water (s) = 1cal / g-c

(b) mass of water (m) = 1ginitial temperature (T1) = 0 cFinal temperature (T2) = 100 cspecific heat of water (s) = 1cal / g-cheat energy transferred  Q = ms (T2-T1)

(b) mass of water (m) = 1ginitial temperature (T1) = 0 cFinal temperature (T2) = 100 cspecific heat of water (s) = 1cal / g-cheat energy transferred  Q = ms (T2-T1)                                    Q = 1x1x(100-0)

(b) mass of water (m) = 1ginitial temperature (T1) = 0 cFinal temperature (T2) = 100 cspecific heat of water (s) = 1cal / g-cheat energy transferred  Q = ms (T2-T1)                                    Q = 1x1x(100-0)                                        = 100 cal

(b) mass of water (m) = 1ginitial temperature (T1) = 0 cFinal temperature (T2) = 100 cspecific heat of water (s) = 1cal / g-cheat energy transferred  Q = ms (T2-T1)                                    Q = 1x1x(100-0)                                        = 100 cal100 cal is the temperature 

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