Question

Answer these all !!!​

Answer 1

SOLUTION.

Equation of the line perpendicular to ax+by+c=0

is always equal to bx - ay+∆=0

where ∆ is different constant from c

{7}

EQUATION......3x+5y-8=0

Equation of the line perpendicular to the giv n line is given as.

5x-3y+∆=0

As this line has intercept of -3 on X axis so the point of intersection with X axis is given as (-3,0) this point satisfies the equation the perpendicular line.

5(-3)-3(0)+∆=0

∆=15

EQUATION REQUIRED

5x-3y+15=0

{8}

EQUATION......3x+2y-8=0

Equation of line perpendicular to the given line is 2x-3y+∆=0.

MID POINT OF THE GIVEN POINTS.

$x = \frac{6 + 4}{2} \\ x = 5 \\ \\ y = \frac{4 - 2}{2} \\ y = 1$

(X,y)=(5,1)

As this point satisfies the perpendicular line.

2(5)-3(1)+∆=0

∆= -7

EQUATION REQUIRED

2x-3y-7=0

{9}

Equation of the line passes through the (2,0) and (2,3) is given as

X=2

You can predict the EQUATION accurately just look at the X coordinate of the points than you find the both have same X coordinate hence equation is X=2

Extra point

A line perpendicular to X=a is given as Y=b

where a and b are two different constants so the line perpendicular to X=2 is given as

Y=∆

so the y coordinate of the intersection point of both the lines is the value of ∆

by section formula we get the value...

which is

MY ANDROID IS NOT ALLOWING ME TO DO THE CALCULATIONS.

REQUIRED EQUATION

Y=2

Answer 2

Step-by-step explanation:

hello frnds ....before answer will help u

so mark him as a brinlist...

hope u all understood