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1 answer is 20;21;22
ashutosh157:
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Ravinder Singh
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II Given sum of consecutive integers is 63
So integers are in A. P.
LET nos are a-d a, a+d.
A. T. Q. :-
a-d+a+a+d= 63
3a= 63
a=21
Nos are consecutive
20,21,22
So integers are in A. P.
LET nos are a-d a, a+d.
A. T. Q. :-
a-d+a+a+d= 63
3a= 63
a=21
Nos are consecutive
20,21,22
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